剛下課,中五生 Woody 問:如何判別一點是否在三角形內?
即已知 A(a,b), B(c,d), C(e,f),如何知道 D(x,y) 是否在三角形 ABC 內?
畫一個準確的圖當然可以,但這不是數學人的答案。
我只想出一個方法: (更多…)
剛下課,中五生 Woody 問:如何判別一點是否在三角形內?
即已知 A(a,b), B(c,d), C(e,f),如何知道 D(x,y) 是否在三角形 ABC 內?
畫一個準確的圖當然可以,但這不是數學人的答案。
我只想出一個方法: (更多…)
一。釘已打
太太生日,想談更多;但這不宜,只記某刻:她去看衫,兒子上課,我去看書。
基礎數學,頗為有趣,暼見如下:
唯銀根出缺,書釘已打,匆匆離去,滿足。新近一套:《數學文化小叢書》,短小精悍,其中一本,價值 $14,題為《幾何學在文明中所扮演的角色》,著者項武義教授(姑勿論存在關於項教授的負面言論),也吸引了眼目。在起始一段: (更多…)
在測驗中,我隨便擬了一道極顯淺的題:
設直線 及曲線
的方程分別是
及
。若
(的圖像) 切
(的圖像) 於
,求
的坐標。另設
上一點
,其
坐標為 1,求
在
處的法線(normal)之方程。 (更多…)
為讓 NSS 的同學多一點探究,在下嘗試在數學課引入一些活動,其中一個舊活動是「交通擠塞」,見
http://mathforum.org/alejandre/java/jam/Jam.html
當天和同學探究 對「人」和「最少步數」的關係,易知
當 ,「最少步數」是 3;
當 ,「最少步數」是 8;
隨即,我著同學「估」:當 時,「最少步數」如何? (更多…)
When distributing the marked test paper to students, one student, Carman, reminded me that there was a ‘question’ in the following question:
If , find
at the point (
).
Carman said, ‘the point does NOT lie on the curve.’
Good observation! I had to say thank you to him. Although I’m not the setter, I should bear the responsibility of checking the paper.
But a natural follow-up question turns up: what is the meaning of the number we are obtaining? Is the number meaningless or standing for something?
Let’s consider a simple example. (更多…)
It is extremely easy to set up questions about differentiation techniques (but good real life application questions are really rare, esp. at secondary school level), apart from tedious computation, when the differentiation involves parameter, students may have difficulties, like mistaking:
(wrong!)
(wrong!)
Here is a question in recent quiz, which involves parametric equations: (更多…)
It is extremely easy to set up questions on number pattern, like
1, 3, 8, 19, 42, 89, ?
for more details, we may tabulate the question as:

the question is, when , what is the value of
?
My first reply to such kind of question is
“no need to do” (更多…)
以前看小學 ETV,其中有討論:為何車輪的形狀要是圓形?因為圓形車輪可使車輛行駛時平穩,為說明這事,ETV 中虛擬(比方說)三角形車輪的情況,結果車子行駛時上下嚴重搖晃,非常不平穩云云。所謂平穩,乃指在行車時車身和平地距離保持一致,即 常數(見下圖)。

諸君莫見笑,車,豈會如此簡單?平穩與否,起碼和懸掛系統有關。抱歉,我講數而已。
車輪圍繞固定車軸轉動,那麼要保持(所謂的)平穩,車輪必為圓形;但若沒有車軸,純粹好像原始人把重物放置在一排圓木上推動般,那麼除了圓形,還有沒有別的形狀,可以達至「 常數」的效果? (更多…)
這是溫書時期。
1. 有關數列的題目
這是校內 2007-2008 年度純數期終試其中一題:
=======================================
Let {} be a sequence of positive integers. Define sequences {
} and {
} as
. (
)
. (
)
Let . (
)
Show that .
======================================= (更多…)
重點題目:
以下是 2009 CE Additional Mathematics Q.18,同學,看看你可否在 16 分鐘內正確地完成它:
The following figure shows a park AED on a horizontal ground. The park is in the form of a right-angled triangle surrounded by a walking path with negligible width. Henry walks along the path at a constant speed. He starts from point A at 7:00 am. He reaches points B, C and D at 7:10 am, 7:15 am and 7:30 am respectively and returns to A via point E. The angles of elevation of H, the top of a tower outside the park, from A and D are 45 and 30
respectively. At point B, Henry is closest to the point K which is the projection of H on the ground. Let HK = h m.

(a) Express DK in terms of h. (1 mark)
(b) Show that AB = h m. (3 marks)
(c) Find the angle of elevation of H from C correct to the nearest degree. (3 marks)
(d) Henry returns to A at 8:10 am. It is known that the area of the park is 9450 m.
(i) Find h.
(ii) A vertical pole of length 3 cm is located such that it is equidistant from A, D and E. Find the angle of elevation of H from the top of the pole correct to the nearest degree. (5 marks) (更多…)
【其一】 上課材料
To 4E students: you may download the worksheet (2009-04-24) at
f4-additional-mathematics-worksheet-20090424
together with some exploration at
【其二】 笑到喊
形如下式的二元二次方程
– - – - – - (*)
中四的同學知道,其圖像代表著圓形(指實圓圓周 circumference of real circle)。
現在反過來,代表著圓形的方程式,是否一定形如 (*)?(即二元二次)
不一定,以下是一條二元四次方程方程
其圖像,也是圓形。為何? (更多…)
今天考會考數學,同事看卷後,感到題目很淺,考生出來,紛紛說「太淺了,怕取不到 A」云云。
聊舉數例
2009 CE Mathematics Paper I Q.17
Given
A, B, C and D lie on the horizontal ground. CE is perpendicular to the plane ABE.
AC = 28 cm, BC = 25 cm, BD = 6 cm, BE = 24 cm, ABC = 57
.
Find the shortest distance from E to the horizontal ground. (更多…)
To F.4E students
Please visit my forum and do some exploration on some easy geometry questions in the previous quiz by clicking the following.
A F.5 student asked me the following question some days ago, reply now.
A(-3,0) and B(-1,0) are two points and P(x,y) is a variable point such that . Let C be the locus of P.
(a) Show that the equation of C is .
(b) T(a,b) is a point on C. Find the equation of the tangent to C at T.
(c) The tangent from A to C touches C at a point S in the second quadrant. Find the coordinates of S.
(d) L is a straight line which passes through point A and makes an angle with the positive
-axis, where
. Q(x,y) is a point on L such that
. (See the figure below)

(i) Write down the coordinates of Q in terms of r and .
(ii) L cuts C at two distinct points H and K. Let ,
.
(1) Show that are roots of the quadratic equation
.
(2) Find the range of possible values of , giving your answers correct to three significant figures.
(HKCEE 1999) (更多…)
This is a simple question in differentiation.
Let for any real number
, determine
at (1,-1). (更多…)
Students may find the following textbook questions difficult.
Question 1
Refer to the figure below, given that
and
;
;
.
Show that . (更多…)
When giving the following basic trigonometry question in F.4 additional mathematics lesson:
Given , prove that
.
It should be extremely easy, (更多…)
Is giving hints a good way to help students in solving mathematics problems? Urm, sometimes it may not.
Here is a common m.i. question in recent F.4 additional mathematics regular test:
Show that is divisible by 3 for any positive integer
. (更多…)
中四開新課,同學認識一下新「朋友」吧:
正弦 = sine ()
餘弦 = cosine ()
正切 = tangent ()
餘割 = cosecant () 定義:
正割 = secant () 定義:
餘切 = cotangent () 定義:
我今天才知「正割」「餘割」這兩個譯名,慚愧。
在堂上,一般情況下,學生提問,在下多半手起刀落,秒殺解之。今天 4E 同學問了兩個問題,在下不能秒殺:
1. 誰發明 這個符號?
2. 畢氏數組中是否必然存在 3 或 5 的倍數? (更多…)
Just share a minor point in the presentation of M.I.
To prove that a proposition P(n) is true for all positive integers n by using M.I.
We need ‘4′ steps, namely (更多…)
As usual, we start with basic algebraic computation drilling at the beginning of F.4 mathematics lessons. But, I just did some useless mathematical chatting and gave something about infinity (e.g. the discussion of 1 – 1 + 1 – 1 + … ) and they showed their excitment with hands clapping. Well, of course, I switched to serious matter very soon. As expected, most of the students did not know the fact that “zero is an even number” (even, they did not know that zero is an integer). I went through some ‘prerequisite’ questions with them, one is:
(a) [True or false?]
(b) If , then
. [True or false?]
(c) The square roots of 9 are 3 and -3. [True or false?]
(d) If , then
and
. [True or false?]
F.4 students, here are the answers. (更多…)
(明報)8月4日 星期一 05:10
【明報專訊】每年會考放榜 ,鎂光燈總是集中在十優狀元身上,聽他們講自己不必苦讀便取得佳績,希望進入醫學院或環球金融系,舉起勝利手勢讓記者拍照。另一邊廂則請來一堆明星名人,勉勵失意考生不必氣餒,會考零分不等於永遠失敗,順便重溫今天賺大錢的明星,當日慘不忍睹的會考分數。
今天又是放榜天,又會產生一班狀元和一班零分生。A有助找工作嗎?A會幫你賺大錢嗎?到底A的意義是什麼?31歲的許正宇(Chris)和40歲的薛俊良(Isaac),在會考高考合共拿到19個A,就由他們來說19個A之後的故事。 (更多…)
我在工業學校渡過中學生活。已往在工業學校,繪圖是必修科(現在好像稱為『圖象傳意科』)。從中一開始,我們便手拿大大塊的繪圖木版,插著 T 尺上課,每星期也要寫 lettering(功效類似我年代幼稚園練字用的 copy book,不知現在還有嗎?)以打好寫字的基本功。 (更多…)
這是一道中四附加數學題。(相信這樣的好題,在將來的公開試會漸漸式微。)它的根本要問的是:一個固定四邊長度的四邊形,在什麼情況下面積最大?題目在教科書可找,詳表如下:
(更多…)
Obviously, the methods throughout the following sets are completely wrong in general; however, correct answers will be obtained. Try to verify them and explain why it happens. You may read the explanation at the end for confirmation.
(Set 1) Erase the indices
(Set 2) Erase the logarithm
(Set 3) Product to sum
(Set 4) Out of radical sign
(Set 5) Exchange indices
(Set 6) Sum to product
Explanation
Try to prove the following identities to see the reasons why we have equations from set 1 to set 6. (更多…)
中四五的同學應該知道:『圓心角是圓周角的兩倍』(angle at centre twice angle at circumference),即是說,若 是下圖圓形的圓心,則有

反過來說,參下圖,假如知道 ,是否表示,存在圓心是
的圓形,穿過
?

(更多…)
驚恐中。我班的中五同學不懂做
Factorize .
(不變金句:教了,不等於學了)
在中二的課,談到 cross method,我教同學用計算機。Casio 3950p (or 3650p) 較以往好,是它顯示的根(roots)是分數,不是點數,這樣可方便同學寫出答案。中五的同學,若你的 Casio 3950p 還未有 quadratic formula,快快看:
http://intranet.sfxc.edu.hk/it-school/homepage/nwc/casio_%20fx_3950p_quadratic_formula_program.doc
更新日期:2008-02-21 (希望不斷更新。)
免插聲明:本文為修附加數學科的中五同學純粹補底之用,高手勿插,謝謝。
1. 口訣:一冇 trigo,即寫 general
有關 general solution,考生常犯毛病見下
錯!最後一步才寫 general solution 的形式是錯的!
不要到最後一步,而是要一開始便寫,即是
即口訣的:一冇 trigo function 符號(本例是 sin),立即 (係立即!!!) 要寫 general solution 的形式。於是,我們有
才是正確答案。
2. 又 degree 又 radian;個樣衰過 Edit 神
In CE mathematics, we know that there are at least 3 measurements for dispersion, namely, range, inter-quartile range and standard derivation.
Describing or comparing the dispersion of different sets may be a very important application.
About the standard derivation, you may read my old messages for your reference
http://www.hkedcity.net/ihouse_tools/forum/read.phtml?forum_id=27877¤t_page=&i=1159940&t=1159940&v=t
http://www.hkedcity.net/ihouse_tools/forum/read.phtml?forum_id=27877¤t_page=&i=965435&t=959956
Given two numerical data sets A and B.
If we come across the following situations
range of A > range of B and
inter-quartile range of A < inter-quartile range of B
How to compare which set is more dispersed?
Well, you may say, just look at the standard derivation.
OK. If we have the following
range of A > range of B and
inter-quartile range of A > inter-quartile range of B and
standard derivation of A < standard derivation of B
Is it true to draw the conclusion that set B is more dispersed?
Further, how about when (set A set B) such that
range of A = range of B and
inter-quartile range of A = inter-quartile range of B and
standard derivation of A = standard derivation of B
Urm, let me give the following as an example
Set A ={1,10,10,10}
Set B = (1,1,1,10}
Is it true to draw the conclusion that both sets have the same dispersion?
The problem may be something about the vagueness of the concept of “dispersion”. How to resolve it?
以往介紹過一些網上的數學工具,諸如 integrator 及 calc101 等。鑑於部分教師及同學沒有上網習慣,讓我介紹一個離線作業且完全免費的數學工具:Scilab,希望大家用得著。關於這個法國研發的開放軟件,只要大家 google 一下,不難找到更詳盡的資訊,在此不贅。感謝有關研究員之努力及慷慨!幾個月前,我才知這軟件存在,這裡我主要提及它在中學數學的一些應用(再進深的我不懂了):
大家先下載(現時)軟件的最先版本
http://www.scilab.org/download/4.1.2/scilab-4.1.2.exe
安裝後,執行便出現以下版面:
看到閃動著的游標(cursor)嗎?可以輸入東西了。為方便大家『唔駛打』,可下載以下的 text file,之後的例子都在這 file 中,大家可以 copy and paste 來試試例子的效果。
http://johnng.inscyber.net/mathgif2/Scilab-johnmayhk.txt
操作小提示:輸入後,按 Enter 顯示結果。打錯了或想修改某些之前輸入的東西,只要按向上箭咀鍵若干次,重新輸入便可。
數字(Numbers)
以下是一般基本計算機也可處理的運算工作。

這是一些初等函數(elementary functions)的運算,留意其輸入的方式。

更多的函數,比如 arcsin 是 asin(),可參考軟件中的 help file。
多項式(Polynomials)
這裡處理的是一元(single variable)的多項式。對多項式的輸入,我們不能直接輸入諸如 x+1 之類,因為電腦不知道何謂 x,我們要先定義清楚,才可繼續運算。這裡介紹 3 種定義方法:
(1) 直接輸入

(2) 透過系數(coefficients)
當多項式的項數多,直接輸入頗麻煩,我們可以透過系數定義,詳見如下:

留意,不一定用 x,其他字母作 variable 也可,但 coeff 這個就字不能修改。
(3) 透過根 (roots)

方便呀,forming equation 的題目,立即得到結果!
好了,定義了多項式,我們可以進行有關多項式的運算。
1. 基本運算

2. 有關除法

3. 解多項式方程 (solve polynomial equations)

4. 因式分解(factorization)

頗有用的功能!不過,對一些根為『不漂亮』的有理數之多項式,比如 – 7 + 26*x – 19*x^2 + 12*x^3,它的因式分解的答案也同樣『不漂亮』,大家不妨試試及想一想解決方法。(注,我知配合 Maxima.exe 或用 Mathematica 可處理多元的多項式。但不太懂,希望以後再研究一下。)
5. 求最大公因式(GCD)及解丟番圖方程(Diophant equation)
讀 AL Pure Mathematics 的同學注意了,這是 algebra 中輾轉相除法 (Euclidean algorithm) 的題目,感覺如何呢?

6. 補充一下:有關整數求 HCF 及 LCM 的方法

7. 有理函數化成部分分式(resolving into partial fractions)
Partial fractions 這類熱門的 pure mathematics 題目,也可以 Scilab 輕易處理。
顯示的三個ans就是答案了,即
。
矩陣(Matrices)
Scilab 最強大的功能是處理矩陣,諸君請看!開始時,當然要定義矩陣。方法是相當簡單。

好了,定義了矩陣,我們可以進行有關矩陣的運算。

注意:矩陣的 entries,可以是多項式,運算如舊!

這是有關矩陣『自身』的運算,修 Pure Mathematics 的同學,感覺良好嗎?

其他功能
Scilab 可做的遠超上述,除了有關統計數據資料之處理,還有下列一些。但因為別的,常用的軟件也有類似功能,我略舉以下數例作結,圖收拋磚引玉之效。

Given that are non-zero constants such that
and
.
Solve the following simultaneous equations
- – - (1)
– - – (2)
Solution (so-called)
divide (1) by (2), yield
Hence
where
is any integer
上述的答案是錯的,為何?
Just busy with the cheering team practice. For a break, write something quick…
This is a part of the question of 2000-CE-A.Math-Q.10, a typical question.Let .
Show that the maximum and minimum values of are
and
respectively.
When it is given to F.5C students, some of them puzzled and asked, ‘is that something wrong in the question?’ They added, ‘ is maximum and
is minimum.’ How come?
In fact, students’ concept is so vague to give that comment. Saying ” is maximum and
is minimum.” is not clear! They should say something like:
attains its maximum value when
. Hence,
to find maximum value of ,
we put into
,
that is, the maximum value of .
Also, they should say
attains its minimum value when
. Hence,
the minimum value of .
The designer of this question played little tricks on numbers. It may be quite interesting to set up similar question by choosing ’suitable’ numbers and
satisfying
;
maximum value of
;
minimum value of
; and
It is not too easy (or too difficult) to find derivatives of .
Students try to find such function to help me set up A. Math Examination Paper ^_^.
1.

Could you guess that equation of the graph of the curve in red (as shown)? You may say it looks like . Well, it is actually
. Justin discovered that the graphs of
and
are quite similar in shape. Further, the following shows the graph of
which looks similar to the graph of
.

Can we generalize the above as the graph of looks quite ‘similar’ (quite a vague idea actually) to
for
? How to explain that finding? I just gave comment briefly that
‘behaves similarly’ to
in the way that
are multiplied by a non-negative factor. Could you give further comments and explanations?
2.
Many interesting matters have rooms for further discussions. Um, just give you something to ‘play’ with. Can you draw a square? What a silly question. Um, let me refine, could you use one single equation to plot a square with curve plotting software (e.g. Winplot.exe)? I had done one, see

Could you guess the equation of the graph above? Strictly speaking, the above graph is NOT a square (see the trouble corners). How to make the curve above? Just consider:
We all know that the equation of circle is something like
Instead of making the power of 2, how about
or
You may use curve plotting software to see the difference of the graphs of the above curves (could you explain the difference?). When the power of and
is getting larger and larger, what will be the changes? Try to use winplot.exe to check. In fact, the figure I posted is the graph of
. It looks like a square except the situation at corners. Students, can you explain, without using any software, why the shape is something like a square? More, if we consider when the powers of
and
are getter smaller, what will be the changes of the shape of graph? Could you imagine the shape of the graphs of the following
Finally, when the powers are different, any further observation you may discover? As for example
We still have a lot of elementary mathematics stuff for exploring, think more!
Also read
http://www.hkedcity.net/ihouse_tools/forum/read.phtml?forum_id=27877¤t_page=&i=1231449&t=1231383&v=t
http://www.hkedcity.net/ihouse_tools/forum/read.phtml?forum_id=27877¤t_page=&i=358012&t=358012
http://www.hkedcity.net/ihouse_tools/forum/read.phtml?forum_id=27877¤t_page=&i=445770&t=445770
1.
Just start teaching the solving of system of 2-variable linear inequalities. One F.5C student, Yeung, told me that “no solution for parallel lines”, Oops, his comment was too brief but I understood him immediately. Let me refine his observation, as follows.
Consider a system of two 2-variable linear inequalities (x and y are real with no extra restriction), the system MAY have no solution only when two different corresponding straght lines are parallel to each other.
As for example,
The two corresponding lines and
are parallel, and the system above has no solution.
In other words, the (two 2-variable linear inequalities) system MUST be solvable if the system is ‘corresponding to’ two non-parallel lines. Although it’s not something very striking, I appreciate the discovery, because it is totally orignated from a student himself. Now, could you show me the proof of Yeung’s observation?
[But, most of F.5C students were out of mood of attending the lesson that day, may be they thought that the content is TOO EASY.]
2.
To solve ,
we draw , and
divides the x-y plane into 2 regions, namely
and
.
Knowing that lies on
and
satisfies
, that is
, then
is the required region.
That is, represents the solution to the inequality
.
The question is: why we just try one point? Should we try another? Is it possible that there is another point lying on
but
does not satisfy the inequality
? How to prove that “one point is enough for representing the whole region”?
Well, the first thing in my mind is the signed distance (有向距離) from a point to a line.
Additional Mathematics tells us that the distance between a point and a line
is
. The absolute sign is for ensuring non-negative distance. How about getting rid of the absolute sign? The numerator
may be positive, zero or negative. What is the significant geometric meaning of the positive and negative values obtained?
Just tell you the following.
If is positve, then
and
are at the different sides of
(as shown)

If is negative, then
and
are at the same sides of
(as shown)

Back to our questions, if does not lie on
,
must lie on one of the regions
and
. Suppose
lies on
, then all the points on
and
are at the same side of
. Hence any point
lying on
will lead to the result
. Hence one point is enough! It is impossible to have another point
lying on
such that
does not satisfy
.
Please complete the discussion when lies on
.
3.
F.5C students asked, ‘how about the case for 3 or more variables?’ To the best of my memory, we may use simplex method.

Suppose a line cuts a circle
at two distinct points, then, the family of circles passing through the interesting points are given by
. (Um, we all know that
is a circle and
is a straight line, so it is not good to say
,
are equations, just for convenience in presentation onwards.) How about when
touches
?

What is the meaning of in this case? This question and its further questions had been discussed some times ago. Suppose
touches
at
, it is not difficult to ‘guess’ that
represents the family of circles touching
at the
. Well it’s true, but why?In AL pure mathematics textbook, we have the following question.Let
Suppose lies on
.
Show that
represents a circle touches at
for any real value of
.
It is given in the solution that,
since is the tangent to
at
,
represents a circle touches
at
.
First of all, it’s unlikely to come across this type of question in the present public examination, so students, just be calm. For discussion purpose only, do you think that the one-sentence solution given is a proof? (“What is a proof?” or “What is a valid proof” may induce many further mathematical or philosophical discussions, I hope I have time to share it later.)
I think that we need to explain why touches
.
How to show two circles touching each other? There should be many ways. Intuitively, it is not difficult to see. Just think about “common tangent is the limiting case of common chord”. But is it a “proof”? Seems to be not satisfactory. One commonly used method in additional mathematics is to show the distance between centres of two circles is equal to either the sum or the difference of radii. But it’s a nightmare to apply this to the previous question. I tried another way in class and was buried in complicated algebraic operations very soon. Firstly, it’s easy to show lies on
. Then I wrote down the tangent
to
at
. Next, write down the tangent
to
at
. Finally, I’d like to show
is the same as
by showing the corresponding coefficients of
and
and the constant term are in proportion. But, it’s another nightmare.
Trying again, for is a common point of
and
, I’d like to show that the slope of tangent to
at
is exactly the slope of tangent to
at
. Then the amount of calculation is reduced. Here is the sketch.
The tangent to at
is
and hence the slope of tangent at
is
. Besides, to find the slope of tangent to
at
, we differentiate
with respect to
, yield
, hence, putting
, we have
which is the same as the slope of tangent to
at
.
Is it a proof? Or a good proof?
Then, I think another way just after finishing the above proof: method of contradiction. We know that is a common point of
and
. Suppose
does not touch
, then
will cut
at another point
(other than
) (See the figure below). Let
be the line
, obviously,
is NOT
. Now consider the family of circles passing through
and
, i.e.
. Note that
is one of the member of that family, hence
for certain
(here, I must emphasize that
and
stand for equations of circle and line), resulting
which is implying that the line
is the same as (or equivalent to)
, contradicting to the fact that
is NOT
. In this proof, there’s nearly no calculation is involved.

Is it a proof? Or a good proof? Students, could you give another proof?
The remaining case should be, when there is no intersection between and
, what is
? Together with the question asked by Zuson, “what is the meaning of
if
lies insides the circle?”, I need more time to study and present. Just end my utterance here.
Reply to http://www.hkedcity.net/ihouse_tools/forum/read.phtml?forum_id=27877¤t_page=&i=1241115&t=1241115
Refer to the following figure, is a common tangent to
and
, find the equation of
.

There are, at least, two methods to cope with this question. Let me sketch one.
Let be the equation of
. Since
is a tangent to both circles, the distances between centres and
will be radii. Hence we have
and
By squaring the above equations and eliminating , we have
— (*)
Then
Hence (*) can be converted into
By solving and rejecting, we come up with the conclusion that is the equation of
.
Reply to http://www.hkedcity.net/ihouse_tools/forum/read.phtml?forum_id=27877¤t_page=&i=1240450&t=1240450
The proof quoted by Ricky is a problem (not M.I. itself). In the usual procedure in M.I., we need to guarantee (say) by valid logic. However in the so-called proof, on assuming the general election to be held in the
year, we had nothing to say about the situation in the
year, and it is problematic to say證畢 because the so-called proof was incomplete and it could not be a counter-example to establish the statement『我們可以證明 M.I. 並不是經常性成立。』For validity of M.I., you may refer to the following post:http://www.hkedcity.net/ihouse_tools/forum/read.phtml?forum_id=27877¤t_page=&i=926996&t=926996