Quod Erat Demonstrandum

2008/01/09

[CE][AM] 錯在哪裡 – general solutions to trigonometric equations

Filed under: Additional / Applied Mathematics,HKCEE — johnmayhk @ 12:01 下午

Given that a,b are non-zero constants such that |a| < 1 and |b| < 1.

Solve the following simultaneous equations

\sin(x) = a – – – (1)
\cos(x) = b – – – (2)

Solution (so-called)

divide (1) by (2), yield

\tan(x) = \frac{a}{b}

Hence

x = 180^{o}n + \tan^{-1}(\frac{a}{b}) where n is any integer

上述的答案是錯的,為何?

1 則迴響 »

  1. Sorry for not telling you earlier.
    And I’ll not be at school the coming Monday for a laser operation.
    Cna’t figure out how the previous year has gone by.

    迴響 由 Ed' — 2008/01/09 @ 8:23 下午 | 回覆


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