Quod Erat Demonstrandum

2016/06/14

正七邊形

Filed under: Fun — johnmayhk @ 12:07 上午
Tags: , ,

如無必要都唔想拍片,超累的說:

(習題)從片中某些結果不難推出以下命題:

(1) \displaystyle \frac{\sin\frac{3\pi}{7}}{\sin\frac{\pi}{7}} is a root of x^3-2x^2-x+1=0.
(2) \displaystyle 2\cos\frac{3\pi}{7} is a root of x^3-x^2-2x+1=0.

同學,有時間試證。

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